A balanced die is thrown once. Find the proba | vedclass

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(B) There are six elementary outcomes in the experiment of throwing a balanced die once: $1, 2, 3, 4, 5, 6$.Let event $B$ be: 'The number on the die i

Vedclass · Accepted Answer

$\frac{1}{2}$

Vedclass · Answer

(B) There are six elementary outcomes in the experiment of throwing a balanced die once: $1, 2, 3, 4, 5, 6$.Let event $B$ be: 'The number on the die is smaller than $4$.'The outcomes favourable to event $B$ are $1, 2,$ and $3$.Hence,the number of outcomes favourable to event $B$ is $3$.Therefore,the probability $P(B)$ is given by:$P(B) = \frac{	ext{Number of outcomes favourable to } B}{	ext{Total number of possible outcomes}}$$P(B) = \frac{3}{6}$$P(B) = \frac{1}{2}$Thus,the probability of getting a number smaller than $4$ is $\frac{1}{2}$.

$A$ balanced die is thrown once. Find the probability of getting a number smaller than $4$.

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